(x^4-1)(x^2-2x-15)=0

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Solution for (x^4-1)(x^2-2x-15)=0 equation: 


Simplifying
(x4 + -1)(x2 + -2x + -15) = 0

Reorder the terms:
(-1 + x4)(x2 + -2x + -15) = 0

Reorder the terms:
(-1 + x4)(-15 + -2x + x2) = 0

Multiply (-1 + x4) * (-15 + -2x + x2)
(-1(-15 + -2x + x2) + x4(-15 + -2x + x2)) = 0
((-15 * -1 + -2x * -1 + x2 * -1) + x4(-15 + -2x + x2)) = 0
((15 + 2x + -1x2) + x4(-15 + -2x + x2)) = 0
(15 + 2x + -1x2 + (-15 * x4 + -2x * x4 + x2 * x4)) = 0
(15 + 2x + -1x2 + (-15x4 + -2x5 + x6)) = 0
(15 + 2x + -1x2 + -15x4 + -2x5 + x6) = 0

Solving
15 + 2x + -1x2 + -15x4 + -2x5 + x6 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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